Theory of exact differentials
Theory of exact differentials
A differential, $\textrm{d}f$, is said to be exact if: $$ \oint \textrm{d}f = 0 $$ An exact differential, $\textrm{d}f=C_1(x,y)\textrm{d}x + C_2(x,y)\textrm{d}x$, has the following important property: $$ \frac{\partial^2 f}{\partial x \partial y} = \frac{\partial^2 f}{\partial y \partial x} $$ Therefore: $$ \left(\frac{\partial C_1}{\partial y}\right)_x = \left(\frac{\partial C_2}{\partial x}\right)_y $$ which follows by remembering that $\textrm{d}f = \left(\frac{\partial f}{\partial x}\right)_y \textrm{d}x + \left(\frac{\partial f}{\partial y}\right)_x \textrm{d}y$ for an exact differential. Two final useful results can be obtained by comparing coefficients of $\textrm{d}x$ and $\textrm{d}y$ in $\textrm{d}f=C_1(x,y)\textrm{d}x + C_2(x,y)\textrm{d}y$ and $\textrm{d}f = \left(\frac{\partial f}{\partial x}\right)_y \textrm{d}x + \left(\frac{\partial f}{\partial y}\right)_x \textrm{d}y$.
Syllabus Aims
- You should be able to test differentials of the form $\textrm{d}u = C_1(x,y) \textrm{d}x + C_2(x,y) \textrm{d}y$ for exactness.
- You should be able to find the function $u(x,y)$ from a differential of the form $\textrm{d}u = C_1(x,y) \textrm{d}x + C_2(x,y) \textrm{d}y$
Description and link | Module | Author | ||
Some problems involving partial differential equations. | AMA4004 | G. Tribello |
Contact Details
School of Mathematics and Physics,
Queen's University Belfast,
Belfast,
BT7 1NN
Email: g.tribello@qub.ac.uk
Website: mywebsite