Random variables : Exercises
Introduction
Example problems
Click on the problems to reveal the solution
Problem 1
red red | red green | red blue |
green red | green green | green blue |
blue red | blue green | blue blue |
The classical interpretation of probability means all combinations are equally likely. Hence: $$ P = \frac{1}{9} \nonumber $$
Problem 2
Problem 3
Problem 4
- Probability of 0:5 split : 0.06
- Probability of 1:4 split : 0.32
- Probability of 2:3 split : 0.62